![]() ![]() Therefore, since the signal from V3 is not present at the outputs of A1 and A2, the attenuation from V3 at 1 MHz to the mixer outputs is infinite. The 1 MHz inputs that each mixer receives are totally suppressed at the mixer outputs. The reason is that the balanced mixers A1 and A2 each deliver two outputs, one at the sum frequency of 1 MHz plus 1 MHz which equals 2 MHz and the other at the difference frequency of 1 MHz minus 1 MHz which equals zero Hz (hence the name zero frequency IF). However, the Bode plotter does not respond to this. Please consider this zero-frequency IF circuit from my Living Analog blog entitled, Zero frequency IF.įor the input V3, at the same frequency as the local oscillator represented by V1 and V2 at 1 MHz, the signal output at the junction of R3 and R4 replicates the signal input. This is great, but there is a SPICE booby trap waiting for the unwary user of the Bode plotter. In both cases above, the analysis frequency range is 0.001 Hz to 1 GHz. The Bode plotter will simply examine the circuit itself and come up with its Bode plot results with no regard to the chosen excitation frequency. Note that it does not matter what excitation frequency you choose for that source. ![]() To make the Bode plotter work, you need to provide some source of excitation, such as the V1 source shown here. 《MOTIX™ Multi-MOSFET Driver: Best-in-Class Solution for DC Motor Control》□To control up to eight half-bridges with one packaged device ![]()
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